first question find the area of triangle whose two side 24 cm and 10 cm and the perimeter of triangle is 62 CM. second question a field is in the form of parallelogram side 60 M and 40 m and one diagonal 80 find the area
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Ask only one question at a time.
1 ) Let a , b , c are three sides of a triangle.
a = 24 cm , b = 10 cm , c = x cm
it is given that ,
Perimeter of the ∆ = 62 cm
a + b + c = 62 cm
24 + 10 + x = 62
34 + x = 62
x = 62 - 34
x = 28
c = x = 28 cm
By
Heron's formula ,
S = ( a + b + c )/2
s = (62/2 )
s = 31
Area of the ∆ = √s(s-a )(s-b)(s-c)
= √31(31-24)(31-10)(31-28)
=√31×7×3 square units.
I hope this helps you.
: )
Ask only one question at a time.
1 ) Let a , b , c are three sides of a triangle.
a = 24 cm , b = 10 cm , c = x cm
it is given that ,
Perimeter of the ∆ = 62 cm
a + b + c = 62 cm
24 + 10 + x = 62
34 + x = 62
x = 62 - 34
x = 28
c = x = 28 cm
By
Heron's formula ,
S = ( a + b + c )/2
s = (62/2 )
s = 31
Area of the ∆ = √s(s-a )(s-b)(s-c)
= √31(31-24)(31-10)(31-28)
=√31×7×3 square units.
I hope this helps you.
: )
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