Question

First right answer = brainliest answer
21. The potential energy stored in the
wound-up spring of a toy motor-car is 18 J. Ignoring any frictional resistance to motion, find the distance this car (mass 200 g) will travel up a slope of 1 in 5. (Ans. 45.9 cm​

Answer 1

Answer:

the car will travel 45 m up the slope.

Explanation:

The work done by the spring is equal to the gravitational potential energy gained by the car.

The gravitational potential energy gained by the car is given by mgh, where m is the mass of the car, g is the acceleration due to gravity, and h is the height gained by the car.

The height gained by the car is given by the horizontal distance traveled up the slope multiplied by the slope angle.

Let x be the horizontal distance traveled up the slope. Then, tan(1/5) = h/x.

Solving for h, we get h = x/5.

Therefore, mgh = 18 J becomes mg(x/5) = 18 J.

Substituting m = 0.2 kg and g = 9.8 m/s^2, we get x = 18/(0.2 x 9.8 x 1/5) = 45 m.

Therefore, the car will travel 45 m up the slope.