Question

First sum please solutions

Answer 1

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Answer 2

$= \frac{1}{ \sqrt{9} - \sqrt{ 3 } } \times \frac{ \sqrt{9} + \sqrt{3} }{ \sqrt{9} + \sqrt{3} } \\ = \frac{\sqrt{9} + \sqrt{3}}{ \sqrt{9} {}^{2} - \sqrt{3} {}^{2} } \\ = \frac{ \sqrt{9} + \sqrt{3} }{9 - 3} \\ = \frac{ \sqrt{9} + \sqrt{3} }{6}$