Question

first term=3/4,comman difference=1/3, last term=17/12.find number of terms

Answer 1

Hi friend here is your answer.

$\blue{given : a = \frac{3}{4} \: \: d = \frac{1}{3} \: \: a_{n} = \frac{17}{12} \: \: n = ?} \\ \mathfrak{formula : a_{n} = a + (n - 1)d} \\ \green{ \frac{17}{12} = \frac{3}{4} + (n - 1) \frac{1}{3} } \\ \green{ \frac{17}{12} = \frac{3}{4} + \frac{1}{3}n - \frac{1}{3} } \\ \green{ \frac{17}{12} = \frac{3}{4} - \frac{1}{3} + \frac{1}{3} n} \\ \green{ \frac{17}{12} = \frac{9 - 4}{12} + \frac{1}{3} n} \\ \green{ \frac{17}{12} - \frac{5}{12} = \frac{1}{3} n } \\ \green{ \frac{12}{12} = \frac{n}{3} } \\ \green{n = 3}$

Hope my answer will help you.