Question

first term = 30,third term = 300/5=60,what is the common difference?

Answer 1

Answer:

The three terms are 30,100,170

Step-by-step explanation:

The first term a is given by 30, let the common difference be d

Sum of first three terms =300

Sum of n terms of an AP is given by

(n=2)x(2a+(n-1)×xd)

In this case n=3 and a=30

(3÷2)x(60+2d)=300

60+2d=200

2d=140

d=70

The second term is 30+70=100

The third term is 100+70=170

Answer 2

Answer:

first term = 30

second term = 45

third term = 60

therefore common difference is 15