Question

first term and CD of CP 2,7,12​

Answer 1

Here is your answer;

a = 12

a = 12d = 6

a = 12d = 6an = 252

a = 12d = 6an = 252a+(n-1)d = 252

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]= 41/2 (12 + 252)

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]= 41/2 (12 + 252)= 41/2 × 264

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]= 41/2 (12 + 252)= 41/2 × 264= 41 × 132

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]= 41/2 (12 + 252)= 41/2 × 264= 41 × 132= 5412.

a = 12d = 6an = 252a+(n-1)d = 25212 + (n-1)6 = 252n-1 = 240/6n = 41 Sn = n/2 [a + an]= 41/2 (12 + 252)= 41/2 × 264= 41 × 132= 5412.HOPE THIS WILL HELP U :)