Question

first term and common difference of an A.P. are 12 and 4 respectively. if tn=96 find n

Answer 1

first term(t) = 12

common difference (d) = 4

tn=96

t+(n-1) d=96

substitute the values

12+(n-1) 4=96

12+4n-4=96

8+4n=96

4n=96-8

n=88/4

n=22

Answer 2

Answer:

The value of n is 22.

Step-by-step explanation:

Given the first term and common difference of an A.P. are 12 and 4 respectively.

Also if $t_n=96$

we have to find the value of n.

first term(t) = 12  

common difference (d) = 4  

$t_n=96$

$t+(n-1)d=96$

substituting the values

$12+(n-1)4=96$

$12+4n-4=96$

$8+4n=96$

$4n=96-8$

$n=\frac{88}{4}=22$

The value of n is 22.