Question

First term and common difference of an A.P. are 6 and 3 respectively ; find S₂₇.​

Answer 1

Answer:

Solution:

Given a=6d=3

S

27

=

2

n

[2a+(n−1)d]

S

27

=

2

27

[2×6+26×3]

=

2

27

[12+78]

=

2

27

[90]

=1,215

Answer 2

Answer:

a = 6

d = 3

so last term that is l= a+(n-1)d =6+(27-1)3 = 84

so sum of all terms Is

N/2(a+l) = 27/2 (6+84) = 1215

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