Question

first term and common difference of an A.P are 6 and 3 respectively find S37?​

Answer 1

Answer:

1215

Step-by-step explanation:

Solution:

Given a=6d=3

S

27

=

2

n

[2a+(n−1)d]

S

27

=

2

27

[2×6+26×3]

=

2

27

[12+78]

=

2

27

[90]

=1,215

Answer 2

Step-by-step explanation:

Here , a = first term = 6 , d = common difference=3, n = 37

We can find S37 by the formula ,

Sn=n/2[ 2a + ( n- 1 ) d ]

.

.

.

.

.

NOW JUST SUBSTITUTE THE VALUES AND GET THE ANSWER

HOPE IT HELPED YOU