Math, asked by guptajuhi557, 1 year ago

First term and the sum of an infinite G.P are 2 and 3 respectively. Find the common ratio and sum upto n terms

Answers

Answered by pulakmath007
4

SOLUTION

GIVEN

First term and the sum of an infinite G.P are 2 and 3 respectively.

TO DETERMINE

The common ratio and sum upto n terms

EVALUATION

Let a be the First term and r be the Common ratio

Then sum of infinite number of terms

 \displaystyle \sf{ =  \frac{a}{1 - r} }

So by the given condition

 \displaystyle \sf{   \frac{a}{1 - r} = 3 }

 \displaystyle \sf{ \implies \:    \frac{2}{1 - r} = 3 }

 \displaystyle \sf{ \implies \:    3 - 3r = 2}

 \displaystyle \sf{ \implies \:    3r = 1}

 \displaystyle \sf{ \implies \:    r =  \frac{1}{ 3} }

Hence the required common ratio

 \displaystyle \sf{  =  \frac{1}{ 3} }

Now sum of the first n terms

 \displaystyle \sf{ = a \times  \frac{1 -  {r}^{n} }{1 - r}  }

 \displaystyle \sf{ = 2\times  \frac{1 -  { \big(  \frac{1}{3} \big)}^{n} }{1 -  \frac{1}{3} }  }

 \displaystyle \sf{ = 2\times  \frac{1 -  { \big(  \frac{1}{3} \big)}^{n} }{ \frac{2}{3} }  }

 \displaystyle \sf{ = 3\times  \Bigg[  1 -  { \bigg(  \frac{1}{3} \bigg)}^{n}\Bigg]  }

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

1. Find the smallest term of geometric progression 3,5,25/3 that exceeds 100.

https://brainly.in/question/26328002

2. the 6th term of an AP. 2,4,6,8 will be

https://brainly.in/question/30257529

Similar questions