FIRST term if an AP is 4 and the common difference is 3 its 12th term is same as 8th term of another Ap having first term -5.Find the common difference of the second AP
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1
Answer:
6
Step-by-step explanation:
12th term = a + 11d = 4+11×3 = 37
8th term of another ap = a + 7d = -5 +7d
-5+7d = 37
7d = 42
d = 6
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HOLA
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Given , first term = 4 , Common difference = 3
a = 4 , d = 3. ( In first Ap)
{•} Given , A12 ( of first Ap) = A8 ( of second Ap)
{•} In second Ap , First term = - 5
To find d
{•} a12 = a8
( a + 11d) = ( a + 7d)
( 4 + 11(3) ) = ( - 5 + 7d)
( 4 + 33) = ( - 5 + 7d)
37 = - 5 + 7d
5 + 37 = - 7d
42 = -7d ===> d = - 6. { On dividing 42 by 7}
So , the comments difference of second Ap is - 6
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HOPE U UNDERSTAND ❤❤❤❤
===========================
Given , first term = 4 , Common difference = 3
a = 4 , d = 3. ( In first Ap)
{•} Given , A12 ( of first Ap) = A8 ( of second Ap)
{•} In second Ap , First term = - 5
To find d
{•} a12 = a8
( a + 11d) = ( a + 7d)
( 4 + 11(3) ) = ( - 5 + 7d)
( 4 + 33) = ( - 5 + 7d)
37 = - 5 + 7d
5 + 37 = - 7d
42 = -7d ===> d = - 6. { On dividing 42 by 7}
So , the comments difference of second Ap is - 6
=========================
HOPE U UNDERSTAND ❤❤❤❤
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