Question

First term in an A.P is 4 and third term is 8. Identify the second term.​

Answer 1

first term = 4 third term = 8

a= 4 n =3 tn = 8

tn = a + (n-1)d

8 = 4 + 2d

4 = 2d

d = 2

second term = 4 + 2 = 6

Answer 2

Answer:

6

Step-by-step explanation:

T1 : 4

T3: 8

There are 2 ways to find the answer.

Solution 1:

The second term will obviously be the AM of 1st and 3rd term. So, 2nd term = 4+8/2 = 6

Solution 2:

a= 4

2nd term = a+ d

3rd term = a+2d

Now substituting the value of a=4 in 3rd term.

3rd term = a+2d

8 = 4+2d

therefore, d= 2

Now, 2nd term = a+d

= 4+2 = 6

Anwer: 6