first term of A.P. is 5 and the common difference is 4. Complete the activity and find the sum of the first 12 terms of the A.P.
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Step-by-step explanation:
let the number of terms , n = 12
S12 =?
a= 5
d= 4
as we know ,
s = n/2 [2a+(n-1)d]
= 12/2 [2(5)+(12-1)(4)]
= 6 [ 10 +44]
= 324
thus, the sum of first 12 terms of the A.P 324.
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