first term of an a.p is 2 and common difference is 4 find the sum of the 10 terms from the second term to the 11th term
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Answer:
Step-by-step explanation:
a=2
cd=4
a2=2+4=6
a11=a+10d=2+40=42
sn= n/2[ a +an]
sn= 10/2[6+42]
sn=5×48
sn =240
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