Question

first term of an a.p is 2 and common difference is 4 find the sum of the 10 terms from the second term to the 11th term

Answer 1

Answer:

HOPE IT HELPS YOU!!

Step-by-step explanation:

Given: a = 2; d = 4; n = 40;

To find: S40 terms

Formula: Sn=(n/2)∗[2a+(n−1)∗d]

Solution:

S40=(40/2)∗[4+39∗4]

S40=20∗160

S40=3200

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