First term of an AP is 4 and the common difference is 3.its 12th term is same as 8th term of another having first term -5 find the common difference of the second AP
Answers
Answered by
1
Hey mate, here's your solution,
Answer:6
Step-by-step explanation:
T12 = A8
4+11(3)=-5+7(d)
(9+33)/7=d
d=42/7
d=6
Hope it helps you.........
Answered by
1
Given,
First term of First AP= 4 (Let, a¹)
Common difference of first AP= 3 (Let, d¹)
First term of second AP= -5 (Let, a²)
Common difference of second AP= ? (Let, d²)
Now,
12th term of First AP= a¹+11d¹
8th term of second AP= a²+7d²
So,
a¹+11d¹= a²+7d²
4+11*3= -5+7d²
4+33+5= 7d²
42= 7d²
d²= 6
So,
Common difference of second AP= 6
Hope this helps you!
First term of First AP= 4 (Let, a¹)
Common difference of first AP= 3 (Let, d¹)
First term of second AP= -5 (Let, a²)
Common difference of second AP= ? (Let, d²)
Now,
12th term of First AP= a¹+11d¹
8th term of second AP= a²+7d²
So,
a¹+11d¹= a²+7d²
4+11*3= -5+7d²
4+33+5= 7d²
42= 7d²
d²= 6
So,
Common difference of second AP= 6
Hope this helps you!
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