Question

first term of an AP is 5 and its 100th term is -292 find the 50th term

Answer 1

since  a = 5 so  a100 = a + 99d -292 = 5 + 99d 99d = -292 -5 d = - 297 / 99 d = -3 so a50 = a + 49d a50 = 5 + 49(-3)  a50 = 5 - 147 a50 = - 142