First term of ap is 2 and sum of the first five terms is 14 the sum of the next fight terms then find the sum of 20th term
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First term = 2
Let d be the common difference of the A.P.
Therefore, the A.P. is 2, 2 + d, 2 + 2d, 2 + 3d, …
Sum of first five terms = 10 + 10d
Sum of next five terms = 10 + 35d
According to the given condition, =>10+10d = 1/4(10+35d)
=>40+40d = 10+35d
=>30 = −5d
=>d = −6
∴ a20 = a+(20−1)d = 2+(19)(−6) = 2−114 = −112
Hence, the 20th term of the A.P. is –112
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