Question

First term of ap is 2 common difference is 4 calulate sum of its 5 term​

Answer 1

Answer:

Given: a = 2; d = 4; n = 40;

To find: S40 terms

Formula: Sn=(n/2)∗[2a+(n−1)∗d]

Solution:

S40=(40/2)∗[4+39∗4]

S40=20∗160

S40=3200

Thanks for reading!!!

:-)

Step-by-step explanation:

hope it helps...

Answer 2

$Sn = \frac{n}{2} (2a + (n - 1)d)$

n = 5, a = 2, d = 4.

$S5 = \frac{5}{2} (2 \times 2 + (5 - 1) \times 4)$

$S5 = \frac{5}{2} (4 + 16)$

$S5 = \frac{5}{2} (20)$

$S5 = 5 \times 10$

$S5 = 50$

The sum of the first five terms is 50.