Question

first term of the sequence is 10,25th term of the sequence is 490.find the 32nd term?​

Answer 1

Answer:

1057 I think it is but not too sure

Answer 2

Answer:

32nd term is 630.

Step-by-step explanation:

 first term a= 10

                $T_{25}$ = 490

                 490= 10+ (25-1)d

                490-10= 24d

                   d= 480/24

                       =20

               $T_{32}$ = 10+ ( 32-1).20

                     = 10+ 620

                     = 630.