Question

first terms of an arithmetic sequence is ½ and common difference is ⅓ prove that no any natural number present in the sequence?​

Answer 1

Answer:

First term(a)=1/3

Common difference (d)=1/6

a=1/3

a2=⅓+1/6=(2+1)/6=3/6=1/2

a3=½+1/6=(3+1)/6=4/6=⅔

the AP is ⅓, ½,⅔

No it does not contain any natural number