First terms of two AP are 2 and 5 respectively and their common difference are 3 and-2 respectively If the difference of the seems of the first n terms of these two AP are195 .Find the number of terms
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Answer:
n=58
Step-by-step explanation:
solution:-
step I
let first term of two AP be a1 and a2 respectively.
therefore
a1=2 and. a2=5
similarly
let,common difference of two AP be d1 and d2
step II
As per given
sum of n terms of first AP - sum of n terms of another AP=195
therefore by formulae
2a1+(n-1)d1- 2a2+(n-1)d2 =195
2*2+(n-1)*3-2*5+(n-1)*-2=195
4+3n-3-10+2+n=195
1+3n+n-8=195
-7+4n=195
4n=195+7
n=232/4
n=58
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