first three consecutive number whose sum is 108
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hii here is your answer
I hope it's help you
x=first integer
x+1=second integer
x+1+1=third integer
(x)+(x+1)+(x+1+1)=108
3x+3=108
Let's isolate x...
Let's subtract 3 from both sides...
-3+3x+3=108-3
3x=105
Let's divide both sides by 3...
(3x)/3=105/3
x=35
35, 36, 37
Let's check our work...
35+36+37 =? 108
108 =? 108
Yes!
plz marked my answer as brainlist answer
I hope it's help you
x=first integer
x+1=second integer
x+1+1=third integer
(x)+(x+1)+(x+1+1)=108
3x+3=108
Let's isolate x...
Let's subtract 3 from both sides...
-3+3x+3=108-3
3x=105
Let's divide both sides by 3...
(3x)/3=105/3
x=35
35, 36, 37
Let's check our work...
35+36+37 =? 108
108 =? 108
Yes!
plz marked my answer as brainlist answer
pragyadas:
plz marked as brainlist answer
Answered by
0
180 is the sum
x + x + 1 + x + 2 = 108
3x + 3 = 108
3x = 108 - 3
3x = 105
x = 105/3
= 35
Hence, 35 is the value of x
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