Math, asked by ArizQureshi, 1 year ago

first three consecutive number whose sum is 108

Answers

Answered by pragyadas
1
hii here is your answer
I hope it's help you
x=first integer

x+1=second integer

x+1+1=third integer

 

(x)+(x+1)+(x+1+1)=108

3x+3=108

Let's isolate x...

Let's subtract 3 from both sides...

-3+3x+3=108-3

3x=105

Let's divide both sides by 3...

(3x)/3=105/3

x=35

 

35, 36, 37

 

Let's check our work...

35+36+37 =? 108

108 =? 108

Yes!

plz marked my answer as brainlist answer

pragyadas: plz marked as brainlist answer
ArizQureshi: ok
Answered by Anonymous
0

\huge\bf{Answer:-}

180 is the sum

x + x + 1 + x + 2 = 108

3x + 3 = 108

3x = 108 - 3

3x = 105

x = 105/3

= 35

Hence, 35 is the value of x

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