Question

First three terms of an a.P having sum 33 and product 1155. Then 11th term is

Answer 1

Answer:

Step-by-step explanation:

Let 3 terms be a, a+d , a-d

A + a + d + a - d = 33

3a = 33

A = 33/3 = 11

A(a+d)(a-d) = 1155

11 ( 11 + d) (11-d) = 1155

121 - d² = 1155/11

121 - d² = 105

D² = 121 - 105

D² = 16

D = ± 4

If d = +4

A11 = a + (n-1)d

= 11 + (11 - 1)4

= 11 + 40 = 51

If d = -4

A11 = a + (n-1)d

= 11 + (11-1)-4

= 11-40 = -29

Hope it helps uh

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Answer 2

HEY MATE HERE IS YOUR ANSWER--!