Question

First to answer correct gets branliest!!

‘a’ mol of PC15, undergoes, thermal dissociation as :
PC1, PCI, + Cl,, the mole fraction of PCl, at
equilibrium is 0.25 and the total pressure is
2.0 atm. The partial pressure of Cl, at equilibrium
is :-
(1) 2.5
(2) 1.0
(3) 0.5
(4) None

Answer 1

Answer:

Explanation:

PCl5 ⇌ PCl3 + Cl2

 a          0         0

a-n         n         n

Total mole at equilibrium = a-n+n+n = a+n

Partial pressure of PCl3 = Mole fraction x Total pressure

                                      = (n/a+n) x 2.0

                                     = 0.25 x 2 = 0.5

PPCl3 = PCl2 = 0.5atm

Hence, d) is correct.Hope

Answer 2

Answer:

question is tooooooo long