first two digits were 8 and 6 and that the third digit was either 1 or 7,
4th digit can be any number, how many pin numbers were possible?
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A 4 digit PIN number is selected. What is the probability that there are no repeated digits? There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are 10 · 10 · 10 · 10 = 104 = 10000 total possible PIN numbers.
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