Math, asked by sonusharma45, 3 months ago

first wala batao

plzz help me in this question ​

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Answered by ABHINAV012
7

Answer:

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Step-by-step explanation:

A. P = 121, 117, 113 .....

Here , first term , a1 = 121

common difference, d = 117-121

let nth term be the first negative term i.e. an <0

=> a1 + (n-1)d<0

or, 121 +[(n-1)(-4)]< 0

=> 121-4n+4<0

or, 125-4n<0

or, -4n <-125

=> 4n>125

=> 125/4

i.e 31.25

therefore , 32 term will be the first negative term.

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Answered by riya9896
1

Answer:

Given A.P is 121,117,113...............

a=121 and d=117−121=−4

an =a+(n−1)d

=121+(n−1)(−4)

=121−4n+4

=125−4n

We have find the first term of this A.P.

Therefore an <0

125−4n<0

124<4n

n> 125/4

n>31.25

n=32

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