Math, asked by rajmathss, 11 months ago

fish tank can be filled in 10 minutes using both pumps A and B simultaneously. Hospump B can pump water in or out at the same rate. If pump B is inadvertently run inthen the tank will be filled in 30 minutes. How long would it take each pump to fill theitself ? (Use Cramer's rule to solve the problem)​

Answers

Answered by amitnrw
0

Answer:

A alone can fill in 15 mins

B alone can fill in 30 mins

Step-by-step explanation:

Let say pump A alone can fill tank in  A mins

Pump B alone can fill Tank in B  mins

A pump fill in 1 min  = 1/A

B pump fill in 1 min = 1/B

A& B together in 1 min = 1/A + 1/B

1/A + 1/B = 1/10

1/A - 1/B = 1/30

Adding both

2/A = 4/30

=> A = 15

1/15 + 1/B = 1/10

=> 1/B = 1/30

=> B = 30

A alone can fill in 15 mins

B alone can fill in 30 mins

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