Question

fit a second order polynomial to the data given in table 2​

Answer 1

Given : Values of x and y

To Find :  a second order polynomial

Solution:

x y

0 2.1

1 7.7

2 13.6

3 27.2

4 40.9

5 61.1

a second order polynomial

y = 1.860x² + 2.359x + 2.478

R² = 0.998

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Answer 2

Answer: n=input('Number of sets of points : ');

%taking input

for i=1:n

x(i)=input('X(i):');

y(i)=input('Y(i):');

end

%calculating coefficients

sumx=0;

sumy=0;

sumxy=0;

sumxsq=0;

for i=1:n

sumx=sumx+x(i);

sumy=sumy+y(i);

sumxy=sumxy+x(i)*y(i);

sumxsq=sumxsq+x(i)^2;

end

format long ;

%calculating a1 and a0

a1=(n*sumxy-sumx*sumy)/(n*sumxsq-sumx^2) a0=sumy/n-a1*sumx/n

%plotting observed data

plot(x,y,'o')

hold on;

%plotting fitted data

ym=a0+a1.*x;

plot(x,ym);

Step-by-step explanation: