Question

fit's answer will mark as brainliest answer​

Answer 1

Step-by-step explanation:

We have,

$\sqrt{3 - x} = {x}^{2} - x - 1$

Squaring both sides,

For LHS:

$x \leqslant 3$

For RHS:

$x \in( -\frac{5}{4},\infty)$

so, solution set

$( - \frac{5}{4} ,3]$