Question

Fiu. 7.31
4. ABC is a triangle in which altitudes BE and CF to
sides AC and AB are equal (see Fig. 7.32). Show
that
(i). triangleABE=triangleACF
(ii) AB=AC, i.e., ABC is an isosceles triangle.​

Answer 1

Step-by-step explanation:

in Triangle ABE and ACF

<A=<A ( common angle)

AE=AF ( CF bisect AB and BE bisect AC)

<E=<F( each 90°)

∆ABE=∆ACF [ by A-S-A Criteria ]

proved

ii

given that

AB = AC

in isoscele ∆ two sides are equal

so∆ABC IS A ISOSCELE TRINGLE