Question

Five 100 ohm resistors are connected in parallel. If one resistors is removed, the total resistance is?

Answer 1

Answer:

25 ohm

Explanation:

1/R = 1/R1 + 1/R2 + 1/R3 + 1/R4

1/R = 1/100 + 1/100 + 100 + 1/100

1/R = 4/100

1/R = 1/25

Therefore R = 25 ohm.

Answer 2

Answer:-

we have to calculate equivalent resistance of 4resistors .

• R1=R2=R3=R4=100ohm

We know

$\boxed{\sf \dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}\dots}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}+\dfrac{1}{100}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{1+1+1+1}{100}$

$\\ \sf\longmapsto \dfrac{1}{R}=\dfrac{4}{100}$

$\\ \sf\longmapsto R=\dfrac{100}{4}$

$\\ \sf\longmapsto R=25\Omega$