Five burgers, six pizzas and seven cokes cost is ₹178.Six burgers,four pizzas and two cokes cost is ₹124. Find the cost of one burger, one pizza and one coke
Answers
Answer:
1 burger + 1 fries x 1 drink = 25
—————
3 drinks = 30 therefore dividing both sides by 3:
1 drink = 10
—————
1 cup + 2 burgers = 20 so:
10 + 2 burgers = 20 so:
10 + 2 burgers = 10 + 10 so:
2 burgers = 10 therefore dividing both sides by 2:
1 burger = 5
—————
1 burger + 2 fries* = 9 so:
5 + 2 fries = 9 so:
5 + 2 fries = 5 + 4 so:
2 fries = 4 therefore dividing both sides by 2:
1 fries = 2
(*fries is used to mean ‘one order of fries’)
—————
Gathering all of the bits we need we get the following solution:
1 burger + 1 fries x 1 drink = 5 + 2 x 10
Using order of operations (sometimes referred to as BEDMAS or BEMDAS)
Without brackets or exponents the solution to the equation begins with multiplication.
5 + 2 x 10 = 5 + 20 … and then addition:
5 + 20 = 25 therefore:
1 burger + 1 fries x 1 drink = 25.
Answer:
rs. 25
Step-by-step explanation:
1 burger + 1 fries x 1 drink = 25
3 drinks = 30 therefore dividing both sides by 3:
1 drink = 10
1 cup + 2 burgers = 20 so:
10 + 2 burgers = 20 so:
10 + 2 burgers = 10 + 10 so:
2 burgers = 10 therefore dividing both sides by 2:
1 burger = 5
1 burger + 2 fries* = 9 so:
5 + 2 fries = 9 so:
5 + 2 fries = 5 + 4 so:
2 fries = 4 therefore dividing both sides by 2:
1 fries = 2
(*fries is used to mean ‘one order of fries’)
gathering all of the bits we need we get the following solution:
1 burger + 1 fries x 1 drink = 5 + 2 x 10
using order of operations (sometimes referred to as bedmas or bemdas)
without brackets or exponents the solution to the equation begins with multiplication.
5 + 2 x 10 = 5 + 20 … and then addition:
5 + 20 = 25 therefore:
1 burger + 1 fries x 1 drink = 25