Question

Five capacitor and joined in a circuit as shown in the figure. The capacitance of each capacitor is 1.1 microfarad. The equivalent capacitance between points A and B is​

Answer 1

pls refer the attachment first for better understanding

All the capacitors are arranged in parallel combination

Formula for capacitor arranged in parallel combination ,

C eq = C 1 + C 2 + C 3 .... C n

As 5 capacitors each of capacitance 1.1 u F are arranged in parallel combination

C eq = 1.1 + 1.1 + 1.1 +1.1 + 1.1

C eq = 5.5 micro Farad

5.5 is approximately equal to 6

C eq = 6 micro farad