Question

Five cards are drawn from a pack a q
52 cards in how many ways can we select
to one suit and 2 cards belong to another
suit.​

Answer 1

ANSWER

Here n= Total no. of ways m=

52

C

4=

1×2×3×4

52×51×50×49

=13×17×25×49=270725.

There are four honours (ace,king,queen and knave)in each suit and so there are 4 sets of 4 honours each.

To obtain the favourable number of ways, we have to select one suit of four honours from these four sets.

∴m=

4

C

1=4

∴p=required probability =

n

m =

270725

4

Comparing with

541450

k

we get the value of k=8

Please Mark It As Brainlistian