Question

Five cards−ten, jack, queen, king, and an ace of diamonds are shuffled face downwards. One card is picked at random.
(i)What is the probability that the card is a queen?
(ii)If a king is drawn first and put aside, what is the probability that the second card picked up is the ace?

Answer 1

SOLUTION :  

Given : Five cards - ten, jack, queen, king and Ace of diamond are shuffled face downwards

Total number of cards is 5

Total number of outcomes = 5

(i)Let E1 = Event  of getting cards which are queen  

Number of a Cards which are a queen = 1

Number of outcome favourable to E1 = 1

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 1/5 = 1/5

Hence, the required probability of getting Cards which are queen , P(E1) = 1/5

(ii) Given : If a king is drawn first and put aside then

Total number of cards is 4

Total number of outcomes = 4

(i)Let E2 = Event  of getting ace cards

Number of  ace cards = 1

Number of outcome favourable to E2 = 1

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = ¼  

Hence, the required probability of getting ace cards , P(E2) = ¼  

HOPE THIS ANSWER WILL HELP  YOU…

Answer 2

hey mate here is your answer ✌♥✌

here n(s)=5

a)n(E1)=1

so p(E1)=n(E1)/n(s)

=1/5

now when king is removed

b)n(s)=4

n(E2)=1

so p(E2)=n(E2)/n(s)

=1/4

hope it will help you

mark me brainliest ✌✌✌✌