Math, asked by BrainlyHelper, 1 year ago

Five cards − the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random.
(i)What is the probability that the card is the queen?
(ii)If the queen is drawn and put a side, what is the probability that the second card picked up is
(a)an ace?
(b)a queen?

Answers

Answered by nikitasingh79
11

SOLUTION :  

Given : Five cards - ten, jack, queen, king and Ace of diamond are shuffled face downwards

Total number of cards is 5

Total number of outcomes = 5

(i)Let E1 = Event  of getting cards which are queen  

Number of a Cards which are a queen = 1

Number of outcome favourable to E1 = 1

Probability (E1) = Number of favourable outcomes / Total number of outcomes

P(E1) = 1/5 = 1/5

Hence, the required probability of getting Cards which are queen , P(E1) = 1/5

 

(ii) Given : If a queen is drawn first and put aside then

Total number of cards is 4

Total number of outcomes = 4

(a) Let E2 = Event  of getting ace cards

Number of  ace cards = 1

Number of outcome favourable to E2 = 1

Probability (E2) = Number of favourable outcomes / Total number of outcomes

P(E2) = ¼  

Hence, the required probability of getting Cards which are ace , P(E2) = 1/4

(b)  Let E3 = Event  of getting queen cards

Number of queen cards = 0

Number of outcome favourable to E3 = 0

Probability (E3) = Number of favourable outcomes / Total number of outcomes

P(E3) = 0/4 = 0

Hence, the required probability of getting Cards which are queen , P(E3) = 0.

HOPE THIS ANSWER WILL HELP  YOU…

Answered by siddhartharao77
9

Answer:

1/5, 1/4, 0

Step-by-step explanation:

Given, Total number of cards n(S) = 5.

(i) Card is Queen:

Let A be the event of drawing a card which is Queen.

n(A) = 1

Required probability,P(A) = n(A)/n(S)

                                          = 1/5.



If a queen is drawn and put aside, then total number of cards is n(S) = 4

(ii)

(a) an ace:

Let B be the event of drawing a card which is an ace.

n(B) = 1.

Required probability P(B) = n(B)/n(S)

                                          = 1/4


(b) a queen:

Let C be the event of drawing a card which is queen.

n(C) = 0. {As the queen are pus aside}

Required probability P(C) = n(C)/n(S)

                                           = 0.



Hope it helps!

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