Question

Five children take part in a tournament. everyone has to play with one another. how many games must they play

Answer 1

Answer-10
first one will play with 4 others,second one with 3,third one with 2,and the fourth one will play with the remaining one.
4+3+2+1=10
Hopw it will help

Answer 2

10 games as first person which other 4, second with other 3 but not with the first one then match of 3 with the 2 other than first and second and fourth with 1 left other than first 3 players so no. of maths will be 4+3+2+1=10


hope it helps.......