five consecutive whole numbers add up after the middle one has been doubled. Find the smallest of these five numbers.
Answers
Answered by
2
Answer:
Add the five numbers together and set them equal to 100: (n) + (n+1) + (n+2) + (n+3) +(n+4) = 100. Add together the five terms on the left to get 5n + 10 and let that equal 100: 5n +10 = 100. Subtract 10 from both sides: 5n = 90. Divide both sides by 5: n = 18.
Similar questions