Five cubes each of edge 2 cm are joined face to face. The surface area of the cuboid thus formed is :
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Answer:
Side of each cube = 2cm
Five cubes are joined end to end, then length of newly formed cuboid = 2 × 5 = 10 cm
Breadth of newly formed cuboid = 2 cm
Height of newly formed cuboid = 2cm
As we know,
Total surface area of cuboid = 2 (lb + bh + hl)
⇒ 2 (10 × 2 + 2 × 2 + 2 × 10)
⇒ 2 (20+4+20)
⇒ 2 × 44
⇒ 88 cm2
Answered by
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Answer:
surface area of cuboid=2(lb+bh+hl)
2(10×2+2×2+2×10)
2(20+4+20)
44cm^3
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