five cubes of side 3 cm are joined together to form a cuboid find the surface area of generated cuboid
Answers
Answered by
31
Heya !!!
Edge of cube (A) = 3 cm.
Length of resulting cube = 5 × 3 = 15 cm
Height of resulting cuboid = 3 cm
And,
Breadth of resulting cuboid = 3 cm
TSA of resulting cuboid = 2(lB + BH + HL)
=> 2 ( 15 × 3 + 3 × 3 + 3 × 15)
=> 2 ( 45 + 9 + 45)
=> 2 × 99
=> 198 cm².
Hence,
TSA of resulting cuboid = 198 cm².
HOPE IT WILL HELP YOU...... :-)
Edge of cube (A) = 3 cm.
Length of resulting cube = 5 × 3 = 15 cm
Height of resulting cuboid = 3 cm
And,
Breadth of resulting cuboid = 3 cm
TSA of resulting cuboid = 2(lB + BH + HL)
=> 2 ( 15 × 3 + 3 × 3 + 3 × 15)
=> 2 ( 45 + 9 + 45)
=> 2 × 99
=> 198 cm².
Hence,
TSA of resulting cuboid = 198 cm².
HOPE IT WILL HELP YOU...... :-)
Anonymous:
yes i thought there are 3 cubes
Answered by
9
If we join 5 cubes of 3 cm, then
3
[][][][][] 3
<-15-->
Now,
Hieght of resulting cuboid = 3 cm
Breadth of resulting cuboid =3 cm
Length of resulting cuboid = (3×5) = 15 cm
Now,
Surface area of cuboid = 2(lb +bh + hl)
Here,
Surface area = 2[ (15×3)+(3×3)+(3×15)]
Surface are =2[ 45 + 9 + 45]
Surface area = 2×99
Surface area of cuboid = 198 cm²
I hope this will help you
(-:
3
[][][][][] 3
<-15-->
Now,
Hieght of resulting cuboid = 3 cm
Breadth of resulting cuboid =3 cm
Length of resulting cuboid = (3×5) = 15 cm
Now,
Surface area of cuboid = 2(lb +bh + hl)
Here,
Surface area = 2[ (15×3)+(3×3)+(3×15)]
Surface are =2[ 45 + 9 + 45]
Surface area = 2×99
Surface area of cuboid = 198 cm²
I hope this will help you
(-:
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