Five distinct items A B C D and E are to be placed in distinct boxes numbered as 1,2,3,4 &5. Items B and E cannot be grouped together. Maximum number of boxes can be left out without item is?
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Answered by
1
I suppose the answer is 3
Karthik1002:
Yes me also find that answer...but in the book the answer is 2....so confusion
I suppose A , C, D are in the same box and B and E each in separate boxes
But maximum free boxes are free means???
Answered by
5
Since all the items are to be placed in one box or the other,
we place B in box number 1. Then we place E in any other box.
We can place A, C,D in to box with B or with E.
So 3 boxes remain empty. This will be the maximum number of box that can be left out without an item.
we place B in box number 1. Then we place E in any other box.
We can place A, C,D in to box with B or with E.
So 3 boxes remain empty. This will be the maximum number of box that can be left out without an item.
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