Five dry cells each of 1.5 volt have internal resistances of of 0.2, 0.3, 0.4, 0.5 and 12 ohms when connected in series, what current will this 5 sells furnished through 10 ohm resistance
Answers
Answered by
3
R
eq
=r
1
+r
2
+r
3
+r
4
+r
5
+R=0.2+0.3+0.4+0.5+0.6+1
R
eq
=3Ω
$$$E_{eq}=5E=7.5V$
I=
R
eq
E
eq
=
3
7.5
⟹I=2.5A
When battery is shorted , no current flows through R.
Equivalent resistance becomes R
eq
=r
1
+r
2
+r
3
+r
4
+r
5
⟹R
eq
=3Ω
Current=I=
R
eq
E
eq
⟹=I=
2
7
=3.5A
Answer-(D)
Answered by
1
Answer:
ANSWER IS 2A
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