Question

Five electrons have been removed from each atom to form ions. Find the electrostatic force between two such ions when separated by a distance of 4 A°in air

Answer 1

The electrostatic force between two such ions is 3.6 × 10⁻⁸ N.

Five electrons have been removed from each atom to form ions.

We have to find the electrostatic force between two such ions when separated by a distance of 4A° in air.

Concepts :

• Removing electrons from an atom makes it cation.
• Adding electrons to an atom makes it anion.
• Coulomb's law states that the electrostatic force between two charges is directly proportional to the product of magnitude of charges and inversely proportional to the square of separation between them.
• That is, Electrostatic force, F = KqQ/r².

Here, five electrons have been removed from each atom to form ions.

∴ charge on each electron, q = 5e⁻ ,

where e⁻ = charge on each electron = 1.6 × 10⁻¹⁹ C

separation between charges, r = 4 A° = 4 × 10⁻¹⁰ m

Now, F = kq²/r²

= {9 × 10⁹ × (5 × 1.6 × 10⁻¹⁹)²}/{(4 × 10⁻¹⁰)²}

= 3.6 × 10⁻⁸ N

Therefore the electrostatic force between two such ions is 3.6 × 10⁻⁸ N.

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