Five equal resistors when connected in series dissipated 5 W power. ¥ they are connected in parallel, the power dissipated will be (a) 25 W (b) 50 W (c) 100 W (d) 125 W
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Assume voltage is 5 and each resistor is 1 ohm
When all 5 resistors connected in series total resistance is 5 ohms
Power dissipated in all resistors is v^2/r=25/5=5w
If all connected in parallel resultant resistance is 1/5=0.2 ohms
Power dissipated is 25/0.2=125 watts
Explanation:
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