Question

Five friends in a Railway Station weigh themselves in pairs (two of them) on a weighing machine.
The weights are: 129 kgs, 125 kg, 124 kg, 123 kgs, 122 kgs, 121 kgs 120 kgs, 118 kgs, 116 kgs and 114 kgs.
What will be weight of the each one of the five friends if they weigh themselves individually.

*(Note: You got to be 100% correct)*​

Answer 1

a+b=129

b+c=125

c+d=124

d+e=123

a+c=122

a+d=121

a+e=120

b+d=118

b+e=116

c+e=114

Then,

a+b=129

a=129-b.......(eq1)

a+c=122........(eq2)

now put the value of a in equation 2

(129-b)+c=122.......(eq3)

c+b =125......(eq4)

c=125-b........(eq5)

soo put the value of c in equation 3

129-b+125-b=122

254-2b=122

254-122=2b

132=2b

132/2=b

b=66 ( weight of one friend weight is 66)

soo then

a+b =129

a+66=129

a=129-66

a=63(weight of second friend)

b+c=125

66+c=125

c= 125-66

c=59 (weight of third friend)

c+d=124

59+d=124

d=124-59

d=65( weight of fourth friend)

d+e=123

65+e=123

e=123-65

e=58( weight of fifth friend)

HOPE IT MAY HELP YOU

PLZZ MARK AS BRAINLIEST ANSWER