Question

five identical capacitor plates are arranged such that they make capacitors each of 2 micro farad. the plates are connected to a source of emf 10v. the charge on plate c is...​

Answer 1

Answer

Correct option is

B

+40μF

Here four capacitors are in parallel and charge on each is q=CV.

As the plate C is the common plate between the two capacitors so its charge will be double ,i.e,

q=2CV and it is conned to positive terminal of cell so its charge should be positive.

thus, q=2CV=2×2×10=40μC