Five identical resistance coils are connected in the network as shown in fig and the resistance measured between A and B is 1 ohm.Then the individual coils must have a resistance of:-
A) 1 ohm
B) 1/4 ohm
C)7/4 ohm
D)4/7 ohm
Answers
Answer: 7/4
Explanation:
Refer to attached file for explanation
Given : Five identical resistance coils are connected in the network as shown in fig and the resistance measured between A and B is 1 Ω.
To find : the resistance of each resistor.
solution : Let R is the resistance of each resistor.
Three resistors are joined in parallel combination.
let R₁ is the equivalent resistance of three resistors.
so, 1/R₁ = 1/R + 1/R + 1/R
⇒R₁ = R/3
now R₁ and R are joined in series combination.
so equivalent resistance, R₂ = R₁ + R = R + R/3
= 4R/3
finally, R₂ and R are joined in parallel combination.
1/Req = 1/R₂ + 1/R
= 1/(4R/3) + 1/R
= 3/4R + 4/4R
= 7/4R
⇒Req = 4R/7 = 1 Ω
⇒R = 7/4 Ω
Therefore the individual coils must have a resistance of 7/4 Ω.