Question

five irrational numbers between 6 and root 7​

Answer 1

Answer:

$\sqrt{\frac{37}{6}}$, $\sqrt{\frac{19}{3}}$, $\sqrt{\frac{13}{2}}$, $\sqrt{\frac{20}{3}}$, $\sqrt{\frac{41}{6}}$

Step-by-step explanation:

How to solve : We can solve by property of square root.

Taking a square root will not change the inequality,

but only when both are ≥0.

So five examples between 6 and 7 are :

$6\frac{1}{6}$, $6\frac{2}{6}$, $6\frac{3}{6}$, $6\frac{4}{6}$, $6\frac{5}{6}$ or $\frac{37}{6}$, $\frac{19}{3}$, $\frac{13}{2}$, $\frac{20}{3}$, $\frac{41}{6}$

The five irrational numbers are :

$\sqrt{\frac{37}{6}}$, $\sqrt{\frac{19}{3}}$, $\sqrt{\frac{13}{2}}$, $\sqrt{\frac{20}{3}}$, $\sqrt{\frac{41}{6}}$