Five LED bulbs of 8 W each, two fans of 40 W each, an electric motor of 3 kW, and a geyser of
kW are used for 8 hours per day by a family. Calculate the total energy consumed in 30 days and
the cost of electricity used in one day at the rate of 35 per unit.
plz bta do koi
Answers
Answer:
26208
Step-by-step explanation:
5*8=40
2*40=80
1*3000= 3000 total energy consumed is 3120
Answer:
Usage of all Electric bulbs = 8W \times 5 = 40W=8W×5=40W
Usage of all Electric fans = 40W \times 2 = 80W=40W×2=80W
Usage of Electric motor = 3kW = 3000W=3kW=3000W
Usage of Electric geyser = 5kW = 5000W=5kW=5000W
Total Power usage = 40 + 80 + 3000 + 5000 = 8120W=40+80+3000+5000=8120W
Total Power usage in kW =\frac{8120}{1000}=10008120
=8.12 kW=8.12 kW
Total time = 8 hours
∴ Total Energy used = kW \times hours=kW×hours
=8.12 \times 8=8.12×8
=64.96 kWh=64.96kWh
Rate per kWh = ₹5
∴ Total cost for one day = Rate \times kWh=Rate×kWh
= 5 \times 64.96=5×64.96
= 324.8=324.8
Number of days = 30 days
∴ Total cost for 30 days = cost of one day \times× no. of days
= 324.8 \times 30=324.8×30
= 9744=9744
The electricity bill for 30 days is ₹9744.