Math, asked by shashigupta257856, 11 months ago

Five LED bulbs of 8 W each, two fans of 40 W each, an electric motor of 3 kW, and a geyser of
kW are used for 8 hours per day by a family. Calculate the total energy consumed in 30 days and
the cost of electricity used in one day at the rate of 35 per unit.​



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Answers

Answered by yatendersingh0
3

Answer:

26208

Step-by-step explanation:

5*8=40

2*40=80

1*3000= 3000 total energy consumed is 3120

Attachments:
Answered by ankit64462
1

Answer:

Usage of all Electric bulbs = 8W \times 5 = 40W=8W×5=40W

Usage of all Electric fans = 40W \times 2 = 80W=40W×2=80W

Usage of Electric motor = 3kW = 3000W=3kW=3000W

Usage of Electric geyser = 5kW = 5000W=5kW=5000W

Total Power usage = 40 + 80 + 3000 + 5000 = 8120W=40+80+3000+5000=8120W

Total Power usage in kW =\frac{8120}{1000}=10008120

=8.12 kW=8.12 kW

Total time = 8 hours

∴ Total Energy used = kW \times hours=kW×hours

=8.12 \times 8=8.12×8

=64.96 kWh=64.96kWh

Rate per kWh = ₹5

∴ Total cost for one day = Rate \times kWh=Rate×kWh

= 5 \times 64.96=5×64.96

= 324.8=324.8

Number of days = 30 days

∴ Total cost for 30 days = cost of one day \times× no. of days

= 324.8 \times 30=324.8×30

= 9744=9744

The electricity bill for 30 days is ₹9744.

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